Abstract
It is shown that the zero T(a) of the solution y(·,a) of y″+exp (ym−t)=0, y(t,a)→a as t→∞, satisfies
T(a)=(1−(m/2))am+(m−1)log a+log (m/2)+3/2(m−1)+Ol((log 3a)/(am)) as a→∞
if 1≤m<2. This asymptotic expansion of T(a) is related to a result of Atkinson and Peletier (1986). Moreover, if m=2 then
T(a)=log a+s0+O((log 3a)/(am)) as a→∞
where s0=s=1.6853749… is the solution of the transcendental equation
s−1.5=exp (−s).
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