Abstract
Galvanodynamic excursions of Cu in 0·1 Na3PO4 (pH 12·5) yielded two distinct anodic transients in addition to a third ill-defined one, plus two well-defined cathodic potential arrests. A simple method of calculation, from the galvanodynamic trace, of the quantity of electricity consumed along each process is proposed. Addition of Na2SO4 was found to decrease the total quantity of electricity needed to anodically passivate the electrode. cl− addition increased the quantity of electricity corresponding to each anodic process, but by different amounts. At [Cl−] = 1 M, the passivating film did not resist the Cl− attack and signs of rapid breakdown of passivity were observed. A series of steps explaining the effect of Cl−, involving adsorption, interaction with soluble Cu-hydroxy intermediates and finally peptisation of the deposited oxide, is discussed.
Get full access to this article
View all access options for this article.
